find the qoutient and remainder when 6x⁴+11x³+13x²-3x+27 is divided by 3x+4. verify the answer with remainder thorem
rahuldebnath:
plzzz mark as a brainlliest
Answers
Answered by
13
For the remainder theorem we generally use synthetic division.
If (x+2) is a factor of P(x) then x=-2 will be a zero of P(x)
we have P(x) = 2x2-3x+4
The coefficients in descending order from the variable with the highest
exponent to the constant are 2, -3, 4
Write the -2 on the left with a diagonal separating it from the coefficients:
-2 / 2 -3 4 1)bring down the first coefficient (2)
-4 14 2)multiply that by the -2 giving -4
3)bring that product up under the next coefficient
2 -7 18 add down 4 Repeat to the end. Last number is the remainder
The remainder is 18. The remainder theorem says that f(-2)
The polynomial we get when we divide is
(2x2 -3x+4)/(x+2)= 2x-7+ 18/(x+2)
If (x+2) is a factor of P(x) then x=-2 will be a zero of P(x)
we have P(x) = 2x2-3x+4
The coefficients in descending order from the variable with the highest
exponent to the constant are 2, -3, 4
Write the -2 on the left with a diagonal separating it from the coefficients:
-2 / 2 -3 4 1)bring down the first coefficient (2)
-4 14 2)multiply that by the -2 giving -4
3)bring that product up under the next coefficient
2 -7 18 add down 4 Repeat to the end. Last number is the remainder
The remainder is 18. The remainder theorem says that f(-2)
The polynomial we get when we divide is
(2x2 -3x+4)/(x+2)= 2x-7+ 18/(x+2)
Similar questions