Question

Find the quadaratic polynomial if the zeroes are 2+√3/3 abd 2-√3/3

Answer 1

Solving Question:

If and α are β the zeros then,

α + β = -b/a

α * β = c/a

We are given the zeros of the polynomial,therefore we can substitute the values in it to find the answer.

Solution:

α = (2 + √3)/3

β = (2-√3)/3

⇒α + β = -b/a

or, (2+√3)/3 +(2-√3)/3 = -b/a

or, 4/3 = -b/a ........equ(1)

[Multiply 3 so as to make the denominators of equ(1) and equ(2) same ]

⇒ 4/3 * 3/3 = 12/9 = -b/a

⇒ a = 9 ; b = -12

α * β = c/a

or, [(2-√3)/3]* [(2+√3)/3]

or, 2² -(√3)²/9   [∵ (a+b)(a-b) = a² - b² ]

or, 4 -3 /9

or, 1/9  = c/a .........equ(2)

⇒ c = 1

standard form = ax² +bx +c =0

∴ The polynomial is k(9x² - 12x + 1) , where 'k' is a constant.

Answer 2

Answer:

sister plz refer above answer..........................................

Step-by-step explanation: