Question

find the Quadilice polynomial
Zeroes are 3and2
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Answer 1

Answer:

THE FORMULA TO FIND QUADRATIC POLYNOMIAL IS

$k[ {x}^{2} - ( \alpha + \beta )x + ( \alpha \beta )]$

Step-by-step explanation:

$k[{x}^{2} - ( \alpha + \beta )x - ( \alpha \beta )] \\ here, \\ \alpha = 3 \\ \beta = 2 \\ \alpha + \beta \\ = 3 + 2 \\ = 5 \\ \alpha \beta \\ = 3 \times 2 \\ = 6 \\ \\ k[{x}^{2} - (5)x + (6)] \\ k( {x}^{2} - 5x + 6) \\ when \: there \: is \: no \\ denominator \: in \: the \: given \\ zeroes \: then \: \\ k \: value \: becomes \\ \\ 1$

THE QUADRATIC POLYNOMIAL IS

$1( {x}^{2} - 5x + 6) \\ {x}^{2} - 5x + 6$

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