Question

find the quadratic equation for x 4√3x^2 + 5x - 2√3 = 0​

Answer 1

4√3x^2 + 5x - 2√3 = 0

4√3x^2 + 8x - 3x - 2√3 = 0

4x ( √3x + 2) - √3 ( √3x + 2) = 0

( √3x + 2) ( 4x - √3) = 0

( √3x + 2) = 0 or ( 4x - √3) = 0

x = -2/√3 Or x = √3/4




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Answer 2

4 √3x^2 + 5x - 2 √3 = 0
= 4 √3x^2 - 3x + 8x -2 √3 = 0
= √3x (4x - √3) + 2 (4x - √3) = 0
= (√3x + 2) (4x - √3) = 0

(4x - √3) = 0
x= √3/4

(√3x + 2) = 0
x= -2/√3