find the quadratic equation from the roots 3 and -10
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Answer:
The roots are 3 and -10.
sum of the roots = 3+(-10)
-b/a = 3-10 -7
-b/a = -7/1
product of the roots = 3×-10
c/a = -30
c/a = -30/1
Therefore, a = 1 , b = -7 , c= -3000
Required equation = x^2 - ( sum of the roots) x+ (product of the roots)
= x^2 -(-7)x+(-30)
= x^2+7x-30
Step-by-step explanation:
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