Question

Find the quadratic equation having roots 3 and - 4

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

$x^{2} + x- 12$

Step by step explanation: $\alpha = 3\\\beta = -4\\Equation: x^{2} - (\alpha +\beta )x + (\alpha \beta )\\ =x^{2}- (3+(-4))x + (3)(-4)\\ = x^{2} - (3-4)x +(-12)\\=x^{2} +x-12$