Find the quadratic equation if √[5+√5+√5]..........
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Answer:
et f(x)=ax^2+bx+c=0 is qe
and x=√5-√7
factor of f(x) will be
x-√5+√7
now qe=(x+(√7-√5))^2
= x^2+2(√7-√5)x+2(1-6√35)
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