find the quadratic equation if one of the root is root 5 root -3
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Alpha is root 5 and beeta be root-3 so that
( x - root 5 ) ( x - root (-3) ) =0
After multiplication you got this quadritic equation and ans come in form of iota
If you in class 11th or 12th then you attempt this question but you have in class 9 or 10 then for you this question be wrong and answer come out be
X^2 - x (root 5 - root3 iota ) + root5 root3 iota = 0
Hopefully you have got your answer
( x - root 5 ) ( x - root (-3) ) =0
After multiplication you got this quadritic equation and ans come in form of iota
If you in class 11th or 12th then you attempt this question but you have in class 9 or 10 then for you this question be wrong and answer come out be
X^2 - x (root 5 - root3 iota ) + root5 root3 iota = 0
Hopefully you have got your answer
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