Question

find the quadratic equation , if one of the roots is √5 - √3.​

Answer 1

Step-by-step explanation:

let f(x)=ax^2+bx+c=0 is qe

and x=√5-√7

factor of f(x) will be

x-√5+√7

now qe=(x+(√7-√5))^2

= x^2+2(√7-√5)x+2(1-6√35)

Answer 2

The quadratic equation  is  x²+2(√3+√5)x+ (8-2√15)

Step-by-step explanation:

quadratic equation = ax²+bx+c = 0

then

given factor = √5 - √3.​

factor is

x= √5 - √3.​

x-√5 +√3 = 0

then quadratic equation will be

(x+ (√5 +√3))²

using the identity (a+b)²= a²+b²+2ab

then

quadratic equation = x²+2(√3+√5)x+ (8-2√15)

where a = 1 , b = 2(√3+√5) and c = (8-2√15)

hence ,

The quadratic equation  is  x²+2(√3+√5)x+ (8-2√15)

#Learn more:

Evaluate

√2+√(8+2√15)-√(8-2√15)​

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