find the quadratic equation of 4x2-4x-3 verify the relation between its zeroes and coefficients
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POLYNOMIALS
The given quadratic polynomial is,
p(x) =4x2 - 4x - 3
=> 4x2 - 6x + 2x - 3
=> 2x( 2x - 3) + 1(2x + 3)
=> (2x + 1) (2x-3)
p(x) = 0
(2x + 1) = 0 or (2x-3) = 0
x=-1/2 or x= 3/2
Hence, -1/2 and 3/2 are the zeroes of p(x).
Sum of zeroes = -1/2 + 3/2 = 2/2 = 1 =
Coefficient of x / Coefficient of x2
Product of zeroes = (-1/2)(3/2) = -3/4 =
Constant term/ Coefficient of x2
Hope this would help you!!^^
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