Find the quadratic equation which has two roots 5+√3 and 5-√3
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alpha=5+√3
bita=5-√3
alpha+bita =5+√3+5-√3=10
alpha×bita=(5+√3) (5-√3) =25-3=22
x²-(alpha+bita) x+alpha×bita
x²-10x+22
bita=5-√3
alpha+bita =5+√3+5-√3=10
alpha×bita=(5+√3) (5-√3) =25-3=22
x²-(alpha+bita) x+alpha×bita
x²-10x+22
highinspire:
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Answered by
1
Answer:
Step-by-step explanation:
Alpha + beta = 5 + root3 5-roote
=10
Alpha x beta =25 - 3 (5sq - root 3 sq)
=22
Therefore , the polynomial is
X² - (alpha + beta)x +(alpha x beta)
=x² - 10x + 22
This is the required polynomial
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