Question

Find the quadratic equation which solution set is (-2,3)​

Answer 1

Answer:

alpa = -2 and beta = 3

Q = x²- (a + ß) x + a(ß)

Q = x²- (-2+3)x + (-2)3

Q = x²- (1)x - 6

Q = x²- x - 6

$\red{THANK YOU}$

Answer 2

Answer:

x^2 - x - 6 = 0

Step-by-step explanation:

Quadratic equation are written in form of x^2 - Sx + P = 0, where S is the sum of solutions and P is product of solutions. Here,

Sum of solutions = - 2 + 3

                             = 1

Product of solutions = - 2 * 3

                              = - 6

Hence the required equation is :

⇒ x^2 - (1)x + ( - 6 ) = 0

⇒ x^2 - x - 6 = 0