Find the quadratic equation whos rood a
(6+√5) and (6-V3)
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Step-by-step explanation:
given roots = 6+√5 and 6-√3
so it means that x-6-√5=0 and x-6+√3=0
or we can write it as x-√5-6 and x+√3-6=0
Also
(x+√3-6) (x-√5-6) =0
= x(x-√5-6) +√3-6(x-√5-6)
= x²-√5-6x+√3-6x-(√3-6×√5-6)
solve the rest u will get yr answer :)
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