Find the quadratic equation whose one root is 1/3-root2
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1/3-√2 = (3+√2)/7
irrational roots always exist in pairs
So, other root is (3-√2 )/ 7
From this, sum of roots is 6/7
product of roots is 1
Equation is x² - x (sum of roots) + product of roots = 0
x² - 6x/7 + 1 = 0
7x²-6x+7 = 0 is the required quadratic
irrational roots always exist in pairs
So, other root is (3-√2 )/ 7
From this, sum of roots is 6/7
product of roots is 1
Equation is x² - x (sum of roots) + product of roots = 0
x² - 6x/7 + 1 = 0
7x²-6x+7 = 0 is the required quadratic
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