Question

find the quadratic equation whose one root is √ 6​

Answer 1

Step-by-step explanation:

since, one root is

$\sqrt{6}$

Therefore ,other root is (-

$- \sqrt{6}$

So, the equation is

$(x - \sqrt{6} ) \times (x + \sqrt{6} ) = 0 \\ x {}^{2} - 6 = 0 \\ {x }^{2} = 6$