Question

find the quadratic equation whose roots are= (1,2)​

Answer 1

The required quadratic equation is x²-3x+2 = 0.

Given,

The roots of a quadratic equation are 1 and 2.

To Find,

The quadratic equation.

Solution,

The formula for calculating the quadratic equation when its roots are given is

x²-(sum of roots)x+(product of roots)

The given roots are 1 and 2

Sum of roots = 1+2 = 3

product of roots = 1*2 = 2

Now, substituting the values

x²-(3)x+2 = 0

x²-3x+2 = 0

Hence, the required quadratic equation is x²-3x+2 = 0.

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Answer 2

Answer:

The quadratic equation whose roots are= (1,2) is  $x^{2}-3x+2=0$.

Step-by-step explanation:

As per the data given in the question,

The two roots are (1,2)

The standard form of a quadratic equation is: $x^{2} -Sx+P=0$

where, S= sum of roots

and, P= product of roots

So, $S= 1+2 = 3$

and, $P=1\times 2 = 2$

Therefore, the equation is $x^{2}-3x+2=0$.

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