Question

Find the quadratic equation whose roots are 10 and -3​

Answer 1

Answer:

$\boxed{\bf x^2-7x-30}$

Step-by-step explanation:

$roots \ of \ the \ quadratic \ equation \ are \ 10 \ and \ -3. \\\\ \text{sum of roots = 10 + (-3) = 7} \\ \text{product of zeroes = 10(-3) = -30} \\\\\text{The quadratic equation is of the form} \\ \implies x^2-(sum \ of \ zeroes)x+(product \ of \ zeroes0 \\ \implies x^2-[7]x+(-30) \\ \implies x^2-7x-30$

Answer 2

X^2–7X–30

It’s the right answer