find the quadratic equation whose roots are 3+√7 and 3-√7
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X² - 6X + 2
Step-by-step explanation:
QUESTION :-
Find the quadratic equation whose roots are 3 + √7 and 3 - √7.
___________________________
SOLUTION :-
Zeroes = 3+√7 & 3-√7
Sum of zeroes = 3 + √7 + 3 - √7
=> 3 + 3 + √7 - √7
=> 6
Product of zeroes = (3 + √7)(3 - √7)
=> (3)² - (√7)²...[by the formula (a+b)(a-b) = a² - b²]
=> 9 - 7
=> 2
___________________________
Now,
using the quadratic equation formula,
=> x² -(sum of zeroes)x + (product of zeroes)
=> x² -(6)x + (2)
=> x² - 6x + 2
So,
The quadratic equation = x² - 6x + 2
hope it helps.
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