Find the quadratic equation whose roots are 5 and -5
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Answered by
9
Hey!!!
Let S be the sum of the zeros/roots and P be the product of the roots.
Thus S = 5 -5
=> S = 0
Thus P = 5(-5)
=> P = -25
Thus Required Quadratic Equation
=> k(x² - Sx + P)
=> k(x² - 0x - 25)
Thus Answer = x² - 25
Hope this helps
Let S be the sum of the zeros/roots and P be the product of the roots.
Thus S = 5 -5
=> S = 0
Thus P = 5(-5)
=> P = -25
Thus Required Quadratic Equation
=> k(x² - Sx + P)
=> k(x² - 0x - 25)
Thus Answer = x² - 25
Hope this helps
amgothchandan:
Thank you
Answered by
2
S = 5 -5
= S = 0
P = 5(-5)
= P = -25
= k(x² - Sx + P)
= k(x² - 0x - 25)
= x² - 25
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