Find the quadratic equation whose roots are (6 + √5) and
( 6− √5)
Answers
Answered by
2
Answer:
x^2-12x+31=0
Step-by-step explanation:
x^2-(6+√5+6-√5)x+(6+√5)(6-√5)=0
x^2-12x+(36-5)=0
Answered by
0
Answer:
x^2 - 12x 31 = 0
Step-by-step explanation:
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