Math, asked by srishti2270, 8 months ago

Find the quadratic equation whose roots are (6 + √5) and

( 6− √5)

Answers

Answered by srija12345678
2

Answer:

x^2-12x+31=0

Step-by-step explanation:

x^2-(6+√5+6-√5)x+(6+√5)(6-√5)=0

x^2-12x+(36-5)=0

Answered by ishuishu151151
0

Answer:

x^2 - 12x 31 = 0

Step-by-step explanation:

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