find the quadratic equation whose roots are 6-√5 and 6-√5
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Answer:
x²-12x+31
Step-by-step explanation:
The general form of a quadratic equation is given by: x²-(a+b)x+ab , where a & b are the roots of the equation. Thus, if the roots are (6+√5) and (6-√5), the equation =x²-(6+√5+6-√5)x +(6+√5)(6-√5) = x²-12x+31
Therefore, x²-12x+31 is the required quadratic equation.
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Answered by
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(6+√5) (6-√5)
62-√52
30-5
35 answer
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