Find the quadratic equation whose roots are reciprocals of the root of the equation 3 x square - 20 X + 17 is equals to zero
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alpha + beta=20/3...... (1)
alpha*beta=17/3...... (2)
alpha-beta=14/3....... (3)
Now,
It is given that the roots are reciprocals.
Solving (1) and(3) we get,
alpha=17/3. Beta=1
New roots,
alpha=3/17. Beta=1
The quadratic equation is
3X^2-20x+3=0
alpha*beta=17/3...... (2)
alpha-beta=14/3....... (3)
Now,
It is given that the roots are reciprocals.
Solving (1) and(3) we get,
alpha=17/3. Beta=1
New roots,
alpha=3/17. Beta=1
The quadratic equation is
3X^2-20x+3=0
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