Question

find the quadratic equation whose roots are reciprocals of the roots of the equations 3xsquare-20x+17=0

Answer 1

3x square-20x+17=0
3x square-3x-17x+17=0
3x(x-1)-17(x-1)=0
(x-1)(3x-17)=0
x=1 and x=17/3
reciprocal if the roots;
(1/x-1)(1/3x-17)=0
1/(x-1)(3x-17)=0
1/3x square-17x-3x+17=0
1/3x square-20x+17=0
1/3x square-1/20x+1/17=0

Answer 2

3x^2-20x+17=0
3x^2-17x-3x+17=0
3x(x-1)-17(x-1)=0
(x-1)(3x-17)=0
x-1=0,(3x-17)=0
x=1,x=17/3