find the quadratic equation whose roots are the reciprocal of the roots of x2 + 4x - 10 = 0
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roots of x^2+4x-10
-2+√14 & -2-√14
reciprocal of these roots are
1/(-2+√14) & -1/(2+√14)
sum = 2/5
product = 1/10
equation = 10x^2 - 4x + 1
please mark it as the brainliest
-2+√14 & -2-√14
reciprocal of these roots are
1/(-2+√14) & -1/(2+√14)
sum = 2/5
product = 1/10
equation = 10x^2 - 4x + 1
please mark it as the brainliest
Answered by
0
Step-by-step explanation:
roots of x^2+4x-10
-2+√14 & -2-√14
reciprocal of these roots are
1/(-2+√14) & -1/(2+√14)
sum = 2/5
product = 1/10
equation = 10x^2 - 4x + 1
please mark it as the brainliest
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