Question

find the quadratic equation whose roots are twice the roots of 2x^2_5x+2=0​

Answer 1

Answer:

x^2-5x+14=0

Step-by-step explanation:

2x^2-5x+2=0

x=5+✓25-16/4,5-✓25-16/4

x=5+9/4,5-9/4

x=14/4,-4/4

x=7/2,-1

twice the roots=7,-2

x+y=7-2=5

xy=-14

equation is x^2-5x+14=0