Question

Find the quadratic equation whose roots are twice the roots of 2x²-5x+2=0​

Answer 1

Explanation:

Letαandβbetherootofthegivenequation.

Then,α+β=

2

5

andαβ=

2

2

=1

∴2α+2β

∴(α+β)

∴5(2α)(2β)=4

Sotherequiredequationis:

x^2−5x+4=0

Answer 2

Answer:

x=1,1/2

Explanation:

2x2-5x+2=0

2x^2-4x-x+2=0

2x(x-2)-1(x-2)=0

(2x-1)(x-2)=0

so,2x-1=0,x=1/2

x-1=0,x=1

So, X=1/2,1