Find the quadratic.equation whose roots are twice the roots of 2x²-5x+2=0
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Let α and β be the root of the given equation. Then,α+β=25and αβ=22=1∴2α+2β∴(α+β)∴5(2α)(2β)=4 So the required equation is:x2−5x+4=0
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2x2-4x-1x+2
2x (x-2)-1 (x-2)
(2x-1) (x-2)
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