Question

Find the quadratic equation whose roots exceed the roots of the quadratic equation x2-2x+3 by 2​

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Answer 1

Answer:

The answer will be of this question is resolved 2 and 9

Answer 2

Required equation is x2 - 6x + 11 = 0.

Step-by-step explanation:

Given:

$x^2 - 2x + 3 = 0$

Let the roots be α and β

If we consider the roots of required equation at A, B

A = α + 2, B = β  +2  

We know,

αβ  = 3

α + β  = 2

Re plating α, β by x and A, B by x.

x = x - 2

In equation:,

$(\alpha -2)^2-2(\alpha -2) +3=0$

$x ^2+4-4x-2x+4+3=0$

$x^2-6x+11=0$

Required equation.