Question

Find the quadratic equation whose solution set is (2,-3)​

Answer 1

Answer:

x^2 - x -2 =0

x^2 - x - 12=0

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Answer 2

Answer: x² + 6x + (-1)  and x² + 6x + 5

Step-by-step explanation:

Format: x² - (sum of roots)x + (product of roots)

Here,

x = 2   and y = -3

product = -6 and sum = -1  or +5

Therefore,

x² + 6x + (-1)  and x² + 6x + 5