Question

find the quadratic equation whose solution set up is (2,-1)

Answer 1

Step-by-step explanation:

$\: \: by \: the \: formation \: of \: quadratic \: equation$

${x}^{2} - ( \alpha + \beta )x + \alpha \beta = 0$

${x}^{2} - (2 - 1)x + (2)( - 1) = 0$

${x}^{2} - x - 2 = 0 \: is \: the \: correct \: answer$

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