Question

find the quadratic equation whose zeroes are 4 and - 3/5

Answer 1

heya!!

Here is Your Answer.

Given Zeroes :
4 and -3/5

Sum of Zeros- 4-3/5 = 17/5

Product Of Zeroes = 4*(-3/5)
= -12/5

Now, Using Basic Equation of Quadratic Equation, 
p (x) = kx² - (Sum of Zeroes)x + (Product Of Zeroes)
p (x) = x² - 17/5x -12/5

Now, Multiply Whole Equation by 5....
p(x) = 5x² - 17x -12

Hope It Helps.

Answer 2

Hi ,

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Equation of the quadratic polynomial

whose zeroes are m, n is

k[ x² - ( m + n )x + mn ] ,

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Here ,

m = 4 , n = -3/5

m+n = 4 - 3/5 = ( 20 - 3 )/5 = 17/5

mn = 4 × ( -3/5 ) = -12/5

Therefore ,

Required polynomial is

= k[ x² - 17x/5 - 12/5 ]

we take any value k ,

if k = 5

= 5x² - 17x - 12

I hope this helps you.

: )