Question

find the quadratic equation whose zeroes are 5/3 and -3/2

Answer 1

Hello,   Here is ur answer, Formula of a quadratic equation is  x^2 - (sum of roots)x + (product of roots) = 0 Sum of zeroes = (10-9)/6 = 1/6 Product of zeroes = -15/6 So, equation is x^2 - (1/6)x + (-15/6) = 0 x^2 - x/6 + (-15/6) = 0  Multiply both sides by 6 So, 6x^2 - x -15 =0 Is the equation  Hope iit helps u Plz mark it as the Brainliest  

Answer 2

the ans is x= 5/3 and -3/2then (3x-5) and (2x+3)
3x(2x+3)-5(2x+3)
6xsquare+9x-10x-15 =0
6x square -x -15=0
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