Question

find the quadratic equation whose zeroes of polynomials are 5+underroot 2 and 5-underroot 2​

Answer 1

Answer:

x^2 -10x + 21

Step-by-step explanation:

a= 5+√2

b=5-√2

sum of roots= a+b= 5+√2+5-√2= 10

product of roots=ab= (5-√2)(5+√2)=21

quadratic equation= x^2 - (sum of roots)x + product of roots

x^2 -10x + 21

Answer 2

Answer: XPOWER2 - 10X + 23 =0

Step-by-step explanation:

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ZEROS ARE (5+UNDERROOT2) AND (5-UNDERROOT2)

SUM OF ZEROS = 5+UNDERROOT2 + 5- UNDERROOT2 = 10

PRODUCT OF ZEROS=(5+UNDERROOT2)  (5-UNDERROOT2)

                                   =25-2=23

HENCE, REQUIRED EQUATION IS

   XPOWER2-10X+23=0