find the quadratic equation whose zeros are 2 root 7 and minus 2 root 7
Answers
Answered by
2
Sum of zeroes = 2roo7 - 2root7
= 0
Product of zeroes = 2root7 * (-2root7)
= - 28
Required equation = x^2 - (sum of zeroes) x + Product of zeroes = 0
=> x^2 - (0)x +(-28) = 0
=> x^2 - 28 = 0
= 0
Product of zeroes = 2root7 * (-2root7)
= - 28
Required equation = x^2 - (sum of zeroes) x + Product of zeroes = 0
=> x^2 - (0)x +(-28) = 0
=> x^2 - 28 = 0
Answered by
1
this is the answer
fully solved
fully solved
Attachments:
Similar questions