Question

find the quadratic equation whose zeros are 5+√3 and 5-√3​

Answer 1

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Answer 2

Answer:

take α & β as the zeroes of polynomial

α = 5+√3

β = 5-√3

α+β = 5+√3+5-√3 = 10

αβ = (5+√3)(5-√3) = 25-5√3+5√3-3 = 25-3 = 22

p(x)=x²-(sum of zeroes)x+

(product of zeroes)

= x²-(α+β)x+αβ

= x²-(10)x+22

= x²-10x+22

hope it helps.....