Find the quadratic equation with (2 - √3) as one of its root ?
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If (2-√3) be one root of a quadratic equation then the other root will be (2+√3)
∴, sum of the roots = 2-√3+2+√3=4 and product of the roots = (2-√3)(2+√3) = 4-3 =1
Therefore the required quadratic equation is:
x²-(sum of the roots)x+(product of the roots)=0
or, x²-4x+1=0
∴, sum of the roots = 2-√3+2+√3=4 and product of the roots = (2-√3)(2+√3) = 4-3 =1
Therefore the required quadratic equation is:
x²-(sum of the roots)x+(product of the roots)=0
or, x²-4x+1=0
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