find the quadratic equation with the roots 2+√5 and 2-√5
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2
roots = 2 + √5 , 2 - √5
Sum of roots = 2 + √5 + 2 - √5 = 4
Product of roots = (2 +√5)(2 - √5) = 2² - (√5)² = 4 - 5 = -1
Quadratic equation = k [ x² - (sum of roots)x + (product of roots) ]
= k [x² - 4x - 1]
= x² - 4x - 1 (where k = constant)
Hope This Helps You!
Sum of roots = 2 + √5 + 2 - √5 = 4
Product of roots = (2 +√5)(2 - √5) = 2² - (√5)² = 4 - 5 = -1
Quadratic equation = k [ x² - (sum of roots)x + (product of roots) ]
= k [x² - 4x - 1]
= x² - 4x - 1 (where k = constant)
Hope This Helps You!
Answered by
0
(x-2-√5)(x+2+√5)
=(x-2)(x+2+√5)-√5(x+2+√5)
=(x-2)(x+2+√5)-√5(x+2+√5)
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