Question

find the quadratic equation x2+6x+4=0

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Answer 1

Hello !!

Find the coeficients.

A = 1 ; B = 6 ; C = 4

Find the discriminant.

D = b^2 - 4ac

D = 6^2 - 4 × 1 × 4

D = 36 - 16

D = 20

Find the roots.

x = (-b ± √D)/(2a)

x = (-6 ± √20)/(2(1))

x = (-6 ± √20)/(2)

x = (-6 ± 2√5)/(2)

x = (-3 ± √5)

x' = (-3 + √5)

x'' = (-3 - 2√5)

Final result : the solution for quadratric equation is (-3 + √5) and (-3 - √5).

I hope I have collaborated !