find the quadratic equations one of who's roots are 3+√-2
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Answer:
Step-by-step explanation:
x^2 - 6x + 7
One root = 3+ √ -2
Other root will be = 3 -√ -2
product of roots = (3+ √ -2) (3- √ -2) = 9 - 2 = 7
sum of roots = 3+ √ -2+3- √ -2 = 6
Substitute the values...
x^2 - (sum)x + (product)
x^2 -6x +7
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