Question

find the quadratic equations whose roots are 3 & 4​

Answer 1

Step-by-step explanation:

GIVEN: Roots of a quadratic equation = -3 and 4.

TO FIND: The quadratic equation.

SOLUTION: Let the zeroes be a and b. We know that, The standard form of quadratic equation is,

x² - (a + b)x + ab = 0. Sum of zeroes = -3 + 4 = 1. Product of zeroes = -3 × 4 = -12. Now, ==> x² - (1)x + (-12) = 0.

Answer 2

x^2 - (sum of the zeroes)x+(product of zeroes)=0

sum of zeroes =3+4=7

product of zeroes=3×4=12

$the \: quadratic \: equation \: will \: be \\ {x}^{2} - 7x + 12$