Question

find the quadratic formula whose zeroes are -1/4 and 1/4​

Answer 1

P(x)=x^2-Sumx+product
Given zeroes are -1/4 and 1/4
P(x)=x^2-(-1/4+1/4)x+-1/4*1/4
P(x)=x^2-0x-1/16
P(x)=x^2-1/16
So the quadratic polynomial is x^2-1/16
Hope this helps u

Answer 2

Answer:

16x^2-1=0

Step-by-step explanation:

Let the equation be f(x)=> ax^2+bx+c=0

Given Zeroes of quadratic equation is -1/4 and 1/4

i.e α= -1/4 and β= 1/4

then, =>f(x) = (x-α) (x-β)

= (x-{-1/4})(x-1/4)

= (x+1/4) (x-1/4)

= x^2+1/4x-1/4x-1/16

= x^2-1/16

=> 16x^2-1 = 0