Question

find the quadratic polonomoial whose zero are -3 and 4 ​

Answer 1

Answer:

let alpha, beta =-3, 4

now the quadratic equation with roots alpha and beta= x^2-(alpha+beta)x+alphabeta=0

x^2-(-3+4)x+(-3×4)=0

x^2-x-12=0

therefore the required equation is xsquare-x-12=0

Answer 2

Answer:

X^2 + X - 12 = 0

Step-by-step explanation:

we already know that the standard form of a polynomial is

X^2 + ( Alpha + beta ) X + Alpha× beta = 0//

now,

let -3 = Alpha , and 4 = beta

now substitute the values