Question

find the quadratic polynomial alfa =2 beta=-1 and also the number as the sum and product of its zeroes.​

Answer 1

Answer:

Given,

$\alpha = 2$

$\beta = - 1$

Solution,

Sum of zeroes =

$\alpha + \beta = \frac{ - b}{a}$

$2 + ( - 1) = \frac{ - b}{a}$

$1 = \frac{ - b}{a}$

Product of zeroes =

$\alpha \beta = \frac{c}{a}$

$(2)( - 1) = \frac{c}{a}$

$- 2 = \frac{c}{a}$

Therefore,

a=1, b = -1, c = -2

Therefore required quardratic equation is,

${x}^{2} - x - 2$

Sum of zeroes = 1

product of zeroes= -2

Hope it will help you!!