Find the quadratic polynomial and verify the zeroes and coefficients of 5x^2+2x
Answers
Answered by
1
Here is your answer
![5 {x}^{2} + 2x 5 {x}^{2} + 2x](https://tex.z-dn.net/?f=5+%7Bx%7D%5E%7B2%7D+%2B+2x)
![5x(x + 2) 5x(x + 2)](https://tex.z-dn.net/?f=5x%28x+%2B+2%29)
![5x = 0 \\ x + 2 = 0 \\ x = <br />0 \\ x = - 2 5x = 0 \\ x + 2 = 0 \\ x = <br />0 \\ x = - 2](https://tex.z-dn.net/?f=5x+%3D+0+%5C%5C+x+%2B+2+%3D+0+%5C%5C+x+%3D+%3Cbr+%2F%3E0+%5C%5C+x+%3D+-+2)
α+β=-b/a
0-2=-2/1
-2=-2
αβ=c/a
(0)(-2)=0/1
0=0
hope it helps
α+β=-b/a
0-2=-2/1
-2=-2
αβ=c/a
(0)(-2)=0/1
0=0
hope it helps
swatiSaibabalife:
hope it helps
Similar questions