find the quadratic polynomial each with the given number as the zeros of the polynomial 2 +√3 , 2 - 3√3
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Zeroes : 2 + √3 , 2 - √3
Sum of the zeroes = 2 + √3 + 2 - √3
==> sum of zeroes = 4 ...(1)
Also,
Product of the zeroes = (2 - √3)(2 + √3)
==> product of zeroes = 2² - (√3)²
==> product of zeroes = 1 ...(2)
We know,
==> p(x) = x² - (sum of zeroes)x + (product of zeroes)
==> p(x) = x² - 4x + 1
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