Question

Find the quadratic polynomial each with the given numbers as the sum and
product of its zeroes respectively
1)1,1
2) 4,1

Answer 1

❣️ Hi ❣️

Here is your answer =>

(vi) 4,1

sum of zeros =4

product of zeros=1

R.P=K{x2-(sum)x+(product)}

=K{x2-(4)x+(1)}

=K{x2-4x+1}

hence,the quadratic polynomial is x2-4x+1

☺️I hope it will help uh☺️

Answer 2

AnswEr:

$\bold{\underline{\sf{\pink{\;\;Given:-\;\;}}}}$

1) Sum of Zeroes = 1

Product of Zeroes = 1

We know that,

Sum of Zeroes = $\sf(\alpha + \beta)$

Product of Zeroes = $\sf(\alpha\;\beta)$

By using the Formula:-

$\large{\underline{\boxed{\sf{\red{x^2 - (\alpha + \beta)x + (\alpha\; \beta)}}}}}$

$:\implies\sf\; x^2 - 1x + 1$

$:\implies\large{\underline{\boxed{\sf{\red{x^2 - x + 1}}}}}$

$\rule{150}3$

2) Sum of Zeroes = 4

Product of Zeroes = 1

Same as,

$:\implies\sf(\alpha + \beta) = 4$

$:\implies\sf(\alpha\;\beta)= 1$

$:\implies\sf\;x^2 - 4x + 1$

$:\implies\large{\underline{\boxed{\sf{\red{x^2 - 4x + 1}}}}}$

$\rule{150}3$