Find the quadratic polynomial,for the zeroes alpha,beeta given in each case.
{¡}.2,-1
{¡¡}.root3,-root3
{¡¡¡}.1/4,-1
{¡v}.1/2,3/2
Answers
Answered by
0
Answer:
plz use the formula
let me q no 2 for you
ans is
Step-by-step explanation:
Answered by
0
Answer:
plz use the formula
{x}^{2} - ( \alpha + \beta )x + \alpha \beta = 0x
2
−(α+β)x+αβ=0
let me q no 2 for you
ans is
{x}^{2} - 3x
2
−3
Step-by-step explanation:
{x}^{2} - ( \sqrt{3} + ( - \sqrt{3} ))x + \sqrt{3} \times ( - \sqrt{3} )x
2
−(
3
+(−
3
))x+
3
×(−
3
)
{x}^{2} - ( \sqrt{3} - \sqrt{3} )x - \sqrt{3} \times \sqrt{3}x
2
−(
3
−
3
)x−
3
×
3
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