Question

find the Quadratic polynomial for the zeroes
$\alpha \beta$
given in each case. 2-1​

Answer 1

Hey friend,

Here is the solution :-

We know that to form any quadratic polynomial, the formula is :-

${x}^{2} - ( \alpha + \beta )x + \alpha \beta \\ \\ therefore : - \\ \\ {x}^{2} - (2 + ( - 1))x + 2( - 1) \\ \\ {x}^{2} - (2 - 1)x - 2 \\ \\ {x}^{2} - 1x - 2 \\ \\ {x}^{2} - x - 2$

So, the quadratic polynomial is :-

${x}^{2} - x - 2$

✨I hope this will help you....✨