Question

find the quadratic polynomial for this zeros ​

Answer 1

x²-3
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Explanation :-
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Suppose 1st Zero is √3 = $\alpha$

and 2nd Zero is -√3= $\beta$

x²-($\beta$+$\alpha$)+$\beta$×$\alpha$

x²-(√3-√3)x+√3×(-√3)

x² -0x -3

x²-3

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Answer 2

Answer:

X^2 - 3

Step-by-step explanation:

sum of zeros is √3 - √3 = 0

product of zeros is {√3×(-√3)}=-3

quadratic equation of zeros is

X^2 + (0)X + (-3)

=X^2 - 3