Question

Find the quadratic polynomial given the sum and product of zeros are b)2/3 and -1/4

Answer 1

HELLO.......FRIEND!!

THE ANSWER IS HERE,

Sum of zeroes =2/3.

Product of zeroes =-1/4.

The quadratic eq.

$= > \: {x}^{2} - ( \frac{2}{3} )x + ( \frac{ - 1}{4} ) = 0$

$= > \: {x}^{2} - \frac{2x}{3} - \frac{1}{4} = 0$

$= > \: 12 {x}^{2} - 8x - 3 = 0$


:-)Hope it helps u.

Answer 2

Hi Friend !!

Here is ur answer !!!

The required quadratic equation is

x²-(sum of zeroes) x+(product of zeroes)

= x²-(2/3)x + (-1/4)


= x²-2/3 x - 1/4

= 12x²-8x -3 / 12

= 12x²-8x-3


Hope it helps u : )